297. Serialize and Deserialize Binary Tree
hardAsked at AirbnbEncode a binary tree to a string and decode the string back. Airbnb asks this to test pre-order with explicit null markers vs level-order serialization — both work, but pick one and defend it.
By Sam K., Founder, InterviewChamp.AI · Last verified
Source citations
Public interview reports confirming this problem appears in Airbnb loops.
- Glassdoor (2026-Q1)— Airbnb senior+ onsite reports list this as a recurring serialization hard.
- Blind (2025-12)— Recurring in Airbnb backend interview reports.
Problem
Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment. Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure.
Constraints
The number of nodes in the tree is in the range [0, 10^4].-1000 <= Node.val <= 1000
Examples
Example 1
root = [1,2,3,null,null,4,5][1,2,3,null,null,4,5]Example 2
root = [][]Approaches
1. Pre-order DFS with null markers (optimal)
Serialize: DFS pre-order, emit value or '#' for null. Deserialize: split into tokens and recursively consume.
- Time
- O(n)
- Space
- O(n)
function serialize(root) {
const parts = [];
function dfs(node) {
if (!node) { parts.push('#'); return; }
parts.push(String(node.val));
dfs(node.left);
dfs(node.right);
}
dfs(root);
return parts.join(',');
}
function deserialize(data) {
const tokens = data.split(',');
let i = 0;
function build() {
if (i >= tokens.length) return null;
const t = tokens[i++];
if (t === '#') return null;
const node = { val: parseInt(t, 10), left: null, right: null };
node.left = build();
node.right = build();
return node;
}
return build();
}Tradeoff: Recursive, easy to verify. Pre-order with null markers gives unique reconstruction even when values repeat.
2. Level-order BFS with null markers
Serialize: BFS, emit values left-to-right by level including nulls (with pruning of trailing nulls). Deserialize: split tokens, queue-build.
- Time
- O(n)
- Space
- O(n)
function serializeBFS(root) {
if (!root) return '';
const parts = [];
const queue = [root];
while (queue.length) {
const node = queue.shift();
if (!node) { parts.push('#'); continue; }
parts.push(String(node.val));
queue.push(node.left);
queue.push(node.right);
}
while (parts.length && parts[parts.length - 1] === '#') parts.pop();
return parts.join(',');
}
function deserializeBFS(data) {
if (!data) return null;
const tokens = data.split(',');
const root = { val: parseInt(tokens[0], 10), left: null, right: null };
const queue = [root];
let i = 1;
while (queue.length && i < tokens.length) {
const node = queue.shift();
if (i < tokens.length && tokens[i] !== '#') {
node.left = { val: parseInt(tokens[i], 10), left: null, right: null };
queue.push(node.left);
}
i++;
if (i < tokens.length && tokens[i] !== '#') {
node.right = { val: parseInt(tokens[i], 10), left: null, right: null };
queue.push(node.right);
}
i++;
}
return root;
}Tradeoff: Matches the LeetCode visualizer format. Slightly more code than the pre-order version; pick whichever you can write bug-free.
Airbnb-specific tips
Airbnb wants you to defend your encoding choice. Say: 'I'll use pre-order with explicit nulls because the recursion-on-decode mirrors the recursion-on-encode — symmetric and easy to verify. Level-order matches the LeetCode visualizer but requires queue plumbing.' Either is correct; explicit nulls are required regardless.
Common mistakes
- Skipping null markers — then 'left subtree of X' and 'right subtree of X' aren't separable in the output.
- Using a comma as both delimiter and value (negative numbers OK if you parseInt; the comma boundary is safe).
- Returning empty string '' for null roots but not handling it on deserialize.
Follow-up questions
An interviewer at Airbnb may pivot to one of these next:
- Serialize a BST in fewer bytes (LC 449) — BST property allows post-order without nulls.
- Serialize an N-ary tree (LC 428) — same idea, list children with explicit counts or delimiters.
- Streaming serialization — output as nodes are visited; allows trees too large to fit in memory.
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FAQ
Why explicit nulls?
Without them you can't tell whether a node has zero, one, or two children. The encoding wouldn't be invertible.
Pre-order or level-order — which does Airbnb prefer?
Both pass. Pre-order is cleaner to whiteboard; level-order matches the LC visualizer. Defend your choice with one sentence.
Free learning resources
Curated free links for this problem.
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